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puppet subscribe wildcards

asked 2014-11-18 13:07:28 -0600

updated 2014-11-18 16:01:09 -0600

ramindk gravatar image


I want to do the following:

service { 'nagios':
  ensure    => running,
  subscribe => File[ "/etc/nagios/nagios.cfg", "/etc/nagios/hosts/*.cfg", ],

Is there a better way or what am I missing?

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answered 2014-11-18 16:00:05 -0600

ramindk gravatar image

updated 2014-11-18 16:01:41 -0600

There is not a way to use a wild card. However some of the options below may work for you.

It's almost always better to notify in a many to one relationship rather than trying to make sure one thing is subscribing to all. Also masks your commit cleaner because adding a new file is a single stanza rather than needing to touch two.

file { '/etc/nagios/nagios.cfg':
  content => 'blah',
  notify  => Service['nagios'],

If you break your classes up, you can deal with ordering at the class level.

class nagios { 
  include nagios::install, nagios::config, nagios::service

  Class['nagios::install'] -> Class['nagios::config'] ~> Class['nagios::service']

You could also tag resources

file { '/etc/nagios/nagios.cfg':
  content => 'blah',
  tag     => 'nagios',

File <| tag == 'nagios'|> ~> Service['nagios']
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answered 2014-11-18 17:00:49 -0600

Thanks for the answers!

I did end up putting a

notify  => Service['nagios'],

on each file under /etc/nagios, which is not very efficient, but it is solid, and works.

But I do like the tag feature so I will start using that instead, it looks a lot more efficient.

Thanks very much for the tips!


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Asked: 2014-11-18 13:07:28 -0600

Seen: 610 times

Last updated: Nov 18 '14