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why are variables immutable in puppet ?

asked 2016-11-09 10:41:17 -0600

jondoe gravatar image

it's all in the title

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answered 2016-11-09 15:50:42 -0600

Red Cricket gravatar image

Because puppet is a declarative programming language.

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Simple language design choice. Not being able to reassign a variable means that it will always have the same value, which fits well with the declaritive nature of the language.

DarylW gravatar imageDarylW ( 2016-11-09 21:38:36 -0600 )edit

i mean does it serve some technical purpose, i can see how it constrains me(not being to reassign variables, updates hashes and so on) but i don't see why, whay will break if variables were mutable.

jondoe gravatar imagejondoe ( 2016-11-10 02:59:41 -0600 )edit

Nothing would 'break', it would just be different programming languate schemantics..

DarylW gravatar imageDarylW ( 2016-11-10 08:57:01 -0600 )edit

ok thanks.

jondoe gravatar imagejondoe ( 2016-11-10 10:01:33 -0600 )edit

answered 2016-11-13 04:19:05 -0600

Stefan gravatar image

One problem would also be that if you are able to redeclare a variable than parsing order actually matters, which you want to avoid in the puppet language. Think of the following example

class 'foo' {
  $a = 10
  include bar
  $a = 20

class 'bar' {
  notify { 'Test': message => $foo::a }

now what should the bar class print? The "final" value of $a (20) or the value at the specific parsing time (10). But the class bar could have also be included at a second point out of class foo (lets say a third class baz also includes bar).

So in theory immutable variables would even allow something like

notify { "Test": message => $a }
$a = "I am a"

but (unfortunately) parsing order from top to bottom still matters in the puppet language.

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Asked: 2016-11-09 10:41:17 -0600

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Last updated: Nov 13 '16