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How do I use the type file to create diectories like a mkdir -p without having to code all levels

asked 2017-01-27 14:06:02 -0500

jrbast gravatar image

With file type, you can do an ensure => directory, but I want to automate the creation of all lower level directories, line mkdir -p does to create /opt/level1/level2/level3. or how do I build a list of directory entries to create based on the full final directory I want

The only way I know how in puppet is : file { '[/opt", '/opt/level1','/opt/level1/level2']: ensure => directory, }

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You can't. The `file` resource complies with the PP philosophy describing a state _explicitly_. Probably, there's already a custom type, which takes a string, explodes it at each slash, and creates `file` resources for each directory using a loop. But still, it'd be explicit declaration of the dirs.

Kai Burghardt gravatar imageKai Burghardt ( 2017-01-28 04:41:53 -0500 )edit

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answered 2017-01-30 09:14:41 -0500

DarylW gravatar image

The workaround 'module' that I have seen to solve this problem is The below text is copied from it's readme

dirtree This module provides the dirtree function and resource type, both used for recursive directory management.


Will return: ['/usr', '/usr/share', '/usr/share/puppet']

Will return: ["C:\\windows", "C:\\windows\\system32", "C:\\windows\\system32\\drivers"]

dirtree(['/usr/share/puppet', '/var/lib/puppet/ssl', '/var/lib/puppet/modules'])
Will return: ['/usr', '/usr/share', '/usr/share/puppet',
              '/var', '/var/lib', '/var/lib/puppet', '/var/lib/puppet/ssl',

dirtree('/usr/share/puppet', '/usr')
Will return: ['/usr/share', '/usr/share/puppet']

dirtree('/usr/share', '/usr/share/puppet')
Will return: []

dirtree('C:\\windows\\system32\\drivers', 'C:\\windows')
Will return: ['C:\\windows\\system32', 'C:\\windows\\system32\\drivers']

You can use the dirtree function in a class to enumerate all required directories if needed.

 class dirtree {
  # rubysitedir = /usr/lib/ruby/site_ruby/1.8
  $dirtree = dirtree("/var/lib/puppet/ssl", '/var/lib')

  # $dirtree = ['/usr/lib/puppet', '/var/lib/puppet/ssl']
  ensure_resource('file', $dirtree, {'ensure' => 'directory'})

dirtree resource type This resource type will simply ensure the existence of a directory. It cannot and will not manage ownership or permissions. You should use the file resource type for that. It's simply for use in the edge case in which you must use a directory which you cannot fully manage, for one reason or another.


 dirtree { 'a temp dir':
  ensure  => present,
  path    => '/tmp/foo/bar/baz',
  parents => true,

dirtree { 'another temp dir with the same path':
  ensure  => present,
  path    => '/tmp/foo/bar/baz',

file { '/tmp/foo/bar/baz':
  ensure => directory,
  owner  => 'root',
  group  => 'root',
  mode   => '0755',
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answered 2017-01-28 07:49:18 -0500

Vlad gravatar image

I have been using this define:

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Well, I cherish having proper log messages tellin the specific changes. Outright calling mkdir -p doesn't tell what directories have been created and doesn't change the file mode. Also the autorequire feature of the file resource doesn't work (automatic require => File[…] to any managed parent dirs.

Kai Burghardt gravatar imageKai Burghardt ( 2017-01-28 14:34:23 -0500 )edit

There is also a custom type out there that you give it a path, and it will automatically produce an array of directory elements and ensure each one is present. I forget what it is called :/

DarylW gravatar imageDarylW ( 2017-01-29 20:46:59 -0500 )edit

DarylW, If you come across the custom type for automatically producing an array of directory elements, please apps it on... I will try to find it as well. otherwise, an exec with mkdir -p is my work-around for now

jrbast gravatar imagejrbast ( 2017-01-29 21:03:47 -0500 )edit

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Asked: 2017-01-27 14:06:02 -0500

Seen: 79 times

Last updated: Jan 30