Is it possible to have file resource name value as an array [closed]

asked 2017-04-18 07:17:27 -0600

ndevouge
1 ●1 ●1 ●1

Hello,

I want to set file ressource like that :

classe llibrenms::agent {

$scripts = ['dpkg','bind'] file {"/usr/lib/checkmkagent/local/${scripts}": source => "/opt/librenms-agent/agent-local/${scripts}", }

But it gave me :

Failed to apply catalog: Parameter source failed on File[/usr/lib/checkmkagent/local/[dpkg, bind]]: Failed to convert '/opt/librenms-agent/agent-local/[dpkg, bind]' to URI: bad component(expected absolute path component): /opt/librenms-agent/agent-local/[dpkg,%20bind] at /etc/puppetlabs/code/environments/production/modules/snmp/manifests/init.pp:126

What can I do to resolve this ?

Thank you !

}

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Closed for the following reason the question is answered, right answer was accepted by ndevouge
close date 2017-04-20 04:33:47.483164

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answered 2017-04-20 03:42:53 -0600

fvoges

flag of United Kingdom of Great Britain and Northern Ireland

109 ●1 ●7

When you use an array for the title, you can not use variable interpolation. And all the attributes need to be the same for all the resources declared using the array.

In Puppet 4, you can use code like this to do what you want:

$scripts = ['dpkg','bind']
$scripts.each | String $script | {
  file { "/usr/lib/checkmkagent/local/${script}":
    ensure => file,
    source => "/opt/librenms-agent/agent-local/${script}", 
  }
}