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Is it possible to have file resource name value as an array [closed]

asked 2017-04-18 07:17:27 -0600

ndevouge gravatar image


I want to set file ressource like that :

classe llibrenms::agent {

$scripts = ['dpkg','bind'] file {"/usr/lib/checkmkagent/local/${scripts}": source => "/opt/librenms-agent/agent-local/${scripts}", }

But it gave me :

Failed to apply catalog: Parameter source failed on File[/usr/lib/checkmkagent/local/[dpkg, bind]]: Failed to convert '/opt/librenms-agent/agent-local/[dpkg, bind]' to URI: bad component(expected absolute path component): /opt/librenms-agent/agent-local/[dpkg,%20bind] at /etc/puppetlabs/code/environments/production/modules/snmp/manifests/init.pp:126

What can I do to resolve this ?

Thank you !


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Closed for the following reason the question is answered, right answer was accepted by ndevouge
close date 2017-04-20 04:33:47.483164

2 Answers

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answered 2017-04-20 03:42:53 -0600

fvoges gravatar image

When you use an array for the title, you can not use variable interpolation. And all the attributes need to be the same for all the resources declared using the array.

In Puppet 4, you can use code like this to do what you want:

$scripts = ['dpkg','bind']
$scripts.each | String $script | {
  file { "/usr/lib/checkmkagent/local/${script}":
    ensure => file,
    source => "/opt/librenms-agent/agent-local/${script}", 
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In puppet 3, you were able to use the methods to achieve something similar

DarylW gravatar imageDarylW ( 2017-04-21 10:22:29 -0600 )edit

answered 2017-04-20 04:33:24 -0600

ndevouge gravatar image

Wow perfect ! Thank you for your response, it works perfectly :)

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Asked: 2017-04-18 07:17:27 -0600

Seen: 46 times

Last updated: Apr 20 '17